






def 		A_			(		lowercase_					,       lowercase_	)							->int:







 """simple docstring"""

 SCREAMING_SNAKE_CASE							  =						(boundary[1] - boundary[0]) / steps
 SCREAMING_SNAKE_CASE							  =						boundary[0]
 SCREAMING_SNAKE_CASE							  =						boundary[1]
 SCREAMING_SNAKE_CASE							  =						make_points(lowercase_					,       lowercase_					,       lowercase_	)
 SCREAMING_SNAKE_CASE							  =						0.0
 y += (h / 3.0) * f(lowercase_	)
 SCREAMING_SNAKE_CASE							  =						2
 for i in x_i:
  y += (h / 3) * (4 - 2 * (cnt % 2)) * f(lowercase_	)
  cnt += 1
 y += (h / 3.0) * f(lowercase_	)
 return y





def 		A_			(		lowercase_					,       lowercase_					,       lowercase_	)							->Any:







 """simple docstring"""

 SCREAMING_SNAKE_CASE							  =						a + h
 while x < (b - h):
  yield x
  SCREAMING_SNAKE_CASE							  =						x + h





def 		A_			(		lowercase_	)							->Any:  # enter your function here







 """simple docstring"""

 SCREAMING_SNAKE_CASE							  =						(x - 0) * (x - 0)
 return y





def 		A_			(		)							->int:







 """simple docstring"""

 SCREAMING_SNAKE_CASE							  =						0.0  # Lower bound of integration
 SCREAMING_SNAKE_CASE							  =						1.0  # Upper bound of integration
 SCREAMING_SNAKE_CASE							  =						1_0.0  # define number of steps or resolution
 SCREAMING_SNAKE_CASE							  =						[a, b]  # define boundary of integration
 SCREAMING_SNAKE_CASE							  =						method_a(lowercase_					,       lowercase_	)
 print(f'''y = {y}'''	)


if __name__ == "__main__":
      main()












import math





def 		A_			(		lowercase_	)							->List[Any]:







 """simple docstring"""

 SCREAMING_SNAKE_CASE							  =						0
 if n % 2 == 0:
  count += 1
  while n % 2 == 0:
   SCREAMING_SNAKE_CASE							  =						int(n / 2	)
    # the n input value must be odd so that
    # we can skip one element (ie i += 2)

 SCREAMING_SNAKE_CASE							  =						3

 while i <= int(math.sqrt(lowercase_	)	):
  if n % i == 0:
   count += 1
   while n % i == 0:
    SCREAMING_SNAKE_CASE							  =						int(n / i	)
  SCREAMING_SNAKE_CASE							  =						i + 2

 # this condition checks the prime
 # number n is greater than 2

 if n > 2:
  count += 1
 return count


if __name__ == "__main__":
      __UpperCAmelCase      				=							5_1_2_4_2_1_8_3
      print(f'The number of distinct prime factors is/are {exact_prime_factor_count(n)}')
      print(f'The value of log(log(n)) is {math.log(math.log(n)):.4f}')




