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The dataset generation failed
Error code: DatasetGenerationError
Exception: TypeError
Message: Couldn't cast array of type
struct<acid_concentration_tenths: int64, acid_volume: int64, base_concentration_tenths: int64, town_index: int64, mass_numerator: int64, mass_denominator: int64, molar_mass: int64>
to
{'acid_concentration_tenths': Value('int64'), 'acid_volume': Value('int64'), 'base_concentration_tenths': Value('int64'), 'town_index': Value('int64')}
Traceback: Traceback (most recent call last):
File "/usr/local/lib/python3.14/site-packages/datasets/builder.py", line 1827, in _prepare_split_single
for key, table in generator:
^^^^^^^^^
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 613, in wrapped
for item in generator(*args, **kwargs):
~~~~~~~~~^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.14/site-packages/datasets/packaged_modules/json/json.py", line 343, in _generate_tables
self._cast_table(pa_table, json_field_paths=json_field_paths),
~~~~~~~~~~~~~~~~^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.14/site-packages/datasets/packaged_modules/json/json.py", line 132, in _cast_table
pa_table = table_cast(pa_table, self.info.features.arrow_schema)
File "/usr/local/lib/python3.14/site-packages/datasets/table.py", line 2378, in table_cast
return cast_table_to_schema(table, schema)
File "/usr/local/lib/python3.14/site-packages/datasets/table.py", line 2312, in cast_table_to_schema
cast_array_to_feature(
~~~~~~~~~~~~~~~~~~~~~^
table[name] if name in table_column_names else pa.array([None] * len(table), type=schema.field(name).type),
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
feature,
^^^^^^^^
)
^
File "/usr/local/lib/python3.14/site-packages/datasets/table.py", line 1861, in wrapper
return pa.chunked_array([func(chunk, *args, **kwargs) for chunk in array.chunks])
~~~~^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.14/site-packages/datasets/table.py", line 2068, in cast_array_to_feature
_c(array.field(name) if name in array_fields else null_array, subfeature)
~~^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.14/site-packages/datasets/table.py", line 1863, in wrapper
return func(array, *args, **kwargs)
File "/usr/local/lib/python3.14/site-packages/datasets/table.py", line 2158, in cast_array_to_feature
raise TypeError(f"Couldn't cast array of type\n{_short_str(array.type)}\nto\n{_short_str(feature)}")
TypeError: Couldn't cast array of type
struct<acid_concentration_tenths: int64, acid_volume: int64, base_concentration_tenths: int64, town_index: int64, mass_numerator: int64, mass_denominator: int64, molar_mass: int64>
to
{'acid_concentration_tenths': Value('int64'), 'acid_volume': Value('int64'), 'base_concentration_tenths': Value('int64'), 'town_index': Value('int64')}
The above exception was the direct cause of the following exception:
Traceback (most recent call last):
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 1369, in compute_config_parquet_and_info_response
parquet_operations, partial, estimated_dataset_info = stream_convert_to_parquet(
~~~~~~~~~~~~~~~~~~~~~~~~~^
builder, max_dataset_size_bytes=max_dataset_size_bytes
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
)
^
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 948, in stream_convert_to_parquet
builder._prepare_split(split_generator=splits_generators[split], file_format="parquet")
~~~~~~~~~~~~~~~~~~~~~~^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.14/site-packages/datasets/builder.py", line 1694, in _prepare_split
for job_id, done, content in self._prepare_split_single(
~~~~~~~~~~~~~~~~~~~~~~~~~~^
gen_kwargs=gen_kwargs, job_id=job_id, **_prepare_split_args
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
):
^
File "/usr/local/lib/python3.14/site-packages/datasets/builder.py", line 1880, in _prepare_split_single
raise DatasetGenerationError("An error occurred while generating the dataset") from e
datasets.exceptions.DatasetGenerationError: An error occurred while generating the datasetNeed help to make the dataset viewer work? Make sure to review how to configure the dataset viewer, and open a discussion for direct support.
id string | prompt string | completion string | messages list | answer string | subject string | topic string | difficulty string | format string | pedagogy string | language string | mode string | split string | curriculum dict | provenance dict | verification dict | contamination dict | tokenization dict |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
muta2_0f6ec996de9c38649dd4f354 | In a titration in Onitsha, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.4 mol/dm³ NaOH neutralizes 24 cm³ of 1.9 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.9 × 24 ÷ 0.4 = 114 cm³. Final answer: 114 cm³. | [
{
"role": "user",
"content": "In a titration in Onitsha, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.4 mol/dm³ NaOH neutralizes 24 cm³ of 1.9 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 1.9 × 24 ÷ 0.4 = 114 cm³.... | 114 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
"exam_era": "contemporary",
"alignment": "original item; topic-level alignment only"
} | {
"source_id": "muta_verified_stem_v2",
"source_revision": "sha256:97c99eb0d900f8a41bce63cd2352f2d4e24c04def9eb0c12ed54c00eea0a1f51",
"source_split": "generated",
"source_row_id": "generated:294",
"semantic_cluster_id": "formula:neutralization_volume",
"license": "MIT",
"synthetic": true,
"transform": "... | {
"status": "programmatic",
"method": "neutralization_volume",
"expected": "114 cm³",
"observed": "114 cm³",
"verifier_version": "muta-stem-v2.4",
"inputs": {
"acid_concentration_tenths": 19,
"acid_volume": 24,
"base_concentration_tenths": 4,
"town_index": 11
},
"misconception_type": "eq... | {
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} |
muta2_52762feec4100d71289fdd3c | In a titration in Ilorin, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.2 mol/dm³ NaOH neutralizes 14 cm³ of 0.3 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.3 × 14 ÷ 0.2 = 21 cm³. Final answer: 21 cm³. | [
{
"role": "user",
"content": "In a titration in Ilorin, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.2 mol/dm³ NaOH neutralizes 14 cm³ of 0.3 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 0.3 × 14 ÷ 0.2 = 21 cm³. F... | 21 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
"exam_era": "contemporary",
"alignment": "original item; topic-level alignment only"
} | {
"source_id": "muta_verified_stem_v2",
"source_revision": "sha256:97c99eb0d900f8a41bce63cd2352f2d4e24c04def9eb0c12ed54c00eea0a1f51",
"source_split": "generated",
"source_row_id": "generated:594",
"semantic_cluster_id": "formula:neutralization_volume",
"license": "MIT",
"synthetic": true,
"transform": "... | {
"status": "programmatic",
"method": "neutralization_volume",
"expected": "21 cm³",
"observed": "21 cm³",
"verifier_version": "muta-stem-v2.4",
"inputs": {
"acid_concentration_tenths": 3,
"acid_volume": 14,
"base_concentration_tenths": 2,
"town_index": 6
},
"misconception_type": "equal_... | {
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} |
muta2_b66ecb472f2062114ac92001 | In a titration in Bo, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.5 mol/dm³ NaOH neutralizes 90 cm³ of 0.6 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.6 × 90 ÷ 1.5 = 36 cm³. Final answer: 36 cm³. | [
{
"role": "user",
"content": "In a titration in Bo, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.5 mol/dm³ NaOH neutralizes 90 cm³ of 0.6 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 0.6 × 90 ÷ 1.5 = 36 cm³. Final... | 36 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
"exam_era": "contemporary",
"alignment": "original item; topic-level alignment only"
} | {
"source_id": "muta_verified_stem_v2",
"source_revision": "sha256:97c99eb0d900f8a41bce63cd2352f2d4e24c04def9eb0c12ed54c00eea0a1f51",
"source_split": "generated",
"source_row_id": "generated:894",
"semantic_cluster_id": "formula:neutralization_volume",
"license": "MIT",
"synthetic": true,
"transform": "... | {
"status": "programmatic",
"method": "neutralization_volume",
"expected": "36 cm³",
"observed": "36 cm³",
"verifier_version": "muta-stem-v2.4",
"inputs": {
"acid_concentration_tenths": 6,
"acid_volume": 90,
"base_concentration_tenths": 15,
"town_index": 3
},
"misconception_type": "equal... | {
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} |
muta2_82972a730cccebff9bbe105c | In a titration in Onitsha, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.2 mol/dm³ NaOH neutralizes 26 cm³ of 1.1 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.1 × 26 ÷ 0.2 = 143 cm³. Final answer: 143 cm³. | [
{
"role": "user",
"content": "In a titration in Onitsha, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.2 mol/dm³ NaOH neutralizes 26 cm³ of 1.1 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 1.1 × 26 ÷ 0.2 = 143 cm³.... | 143 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
"exam_era": "contemporary",
"alignment": "original item; topic-level alignment only"
} | {
"source_id": "muta_verified_stem_v2",
"source_revision": "sha256:97c99eb0d900f8a41bce63cd2352f2d4e24c04def9eb0c12ed54c00eea0a1f51",
"source_split": "generated",
"source_row_id": "generated:1194",
"semantic_cluster_id": "formula:neutralization_volume",
"license": "MIT",
"synthetic": true,
"transform": ... | {
"status": "programmatic",
"method": "neutralization_volume",
"expected": "143 cm³",
"observed": "143 cm³",
"verifier_version": "muta-stem-v2.4",
"inputs": {
"acid_concentration_tenths": 11,
"acid_volume": 26,
"base_concentration_tenths": 2,
"town_index": 11
},
"misconception_type": "eq... | {
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muta2_033a389ac686374c1eda99c1 | In a titration in Kumasi, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.6 mol/dm³ NaOH neutralizes 84 cm³ of 0.8 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.8 × 84 ÷ 0.6 = 112 cm³. Final answer: 112 cm³. | [
{
"role": "user",
"content": "In a titration in Kumasi, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.6 mol/dm³ NaOH neutralizes 84 cm³ of 0.8 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 0.8 × 84 ÷ 0.6 = 112 cm³. ... | 112 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
"exam_era": "contemporary",
"alignment": "original item; topic-level alignment only"
} | {
"source_id": "muta_verified_stem_v2",
"source_revision": "sha256:97c99eb0d900f8a41bce63cd2352f2d4e24c04def9eb0c12ed54c00eea0a1f51",
"source_split": "generated",
"source_row_id": "generated:1494",
"semantic_cluster_id": "formula:neutralization_volume",
"license": "MIT",
"synthetic": true,
"transform": ... | {
"status": "programmatic",
"method": "neutralization_volume",
"expected": "112 cm³",
"observed": "112 cm³",
"verifier_version": "muta-stem-v2.4",
"inputs": {
"acid_concentration_tenths": 8,
"acid_volume": 84,
"base_concentration_tenths": 6,
"town_index": 8
},
"misconception_type": "equa... | {
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muta2_5895257b604a84c62ec8efae | In a titration in Freetown, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.6 mol/dm³ NaOH neutralizes 78 cm³ of 1.2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.2 × 78 ÷ 0.6 = 156 cm³. Final answer: 156 cm³. | [
{
"role": "user",
"content": "In a titration in Freetown, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.6 mol/dm³ NaOH neutralizes 78 cm³ of 1.2 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 1.2 × 78 ÷ 0.6 = 156 cm³... | 156 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
"exam_era": "contemporary",
"alignment": "original item; topic-level alignment only"
} | {
"source_id": "muta_verified_stem_v2",
"source_revision": "sha256:97c99eb0d900f8a41bce63cd2352f2d4e24c04def9eb0c12ed54c00eea0a1f51",
"source_split": "generated",
"source_row_id": "generated:1794",
"semantic_cluster_id": "formula:neutralization_volume",
"license": "MIT",
"synthetic": true,
"transform": ... | {
"status": "programmatic",
"method": "neutralization_volume",
"expected": "156 cm³",
"observed": "156 cm³",
"verifier_version": "muta-stem-v2.4",
"inputs": {
"acid_concentration_tenths": 12,
"acid_volume": 78,
"base_concentration_tenths": 6,
"town_index": 4
},
"misconception_type": "equ... | {
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muta2_a6bb91ab99f0b059f18be41e | In a titration in Freetown, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.3 mol/dm³ NaOH neutralizes 45 cm³ of 0.2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.2 × 45 ÷ 0.3 = 30 cm³. Final answer: 30 cm³. | [
{
"role": "user",
"content": "In a titration in Freetown, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.3 mol/dm³ NaOH neutralizes 45 cm³ of 0.2 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 0.2 × 45 ÷ 0.3 = 30 cm³.... | 30 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
"exam_era": "contemporary",
"alignment": "original item; topic-level alignment only"
} | {
"source_id": "muta_verified_stem_v2",
"source_revision": "sha256:97c99eb0d900f8a41bce63cd2352f2d4e24c04def9eb0c12ed54c00eea0a1f51",
"source_split": "generated",
"source_row_id": "generated:2094",
"semantic_cluster_id": "formula:neutralization_volume",
"license": "MIT",
"synthetic": true,
"transform": ... | {
"status": "programmatic",
"method": "neutralization_volume",
"expected": "30 cm³",
"observed": "30 cm³",
"verifier_version": "muta-stem-v2.4",
"inputs": {
"acid_concentration_tenths": 2,
"acid_volume": 45,
"base_concentration_tenths": 3,
"town_index": 4
},
"misconception_type": "equal_... | {
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} | {
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"max_sequence_tokens": 1024,
"within_limit": true
} |
muta2_276444e1d9917e23465ba1c2 | In a titration in Accra, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.6 mol/dm³ NaOH neutralizes 60 cm³ of 1.6 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.6 × 60 ÷ 0.6 = 160 cm³. Final answer: 160 cm³. | [
{
"role": "user",
"content": "In a titration in Accra, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.6 mol/dm³ NaOH neutralizes 60 cm³ of 1.6 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 1.6 × 60 ÷ 0.6 = 160 cm³. F... | 160 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
"exam_era": "contemporary",
"alignment": "original item; topic-level alignment only"
} | {
"source_id": "muta_verified_stem_v2",
"source_revision": "sha256:97c99eb0d900f8a41bce63cd2352f2d4e24c04def9eb0c12ed54c00eea0a1f51",
"source_split": "generated",
"source_row_id": "generated:2394",
"semantic_cluster_id": "formula:neutralization_volume",
"license": "MIT",
"synthetic": true,
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muta2_e525d98d3de689cffd33babe | In a titration in Onitsha, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.6 mol/dm³ NaOH neutralizes 176 cm³ of 0.6 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.6 × 176 ÷ 1.6 = 66 cm³. Final answer: 66 cm³. | [
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muta2_96a3659bde11e12a617d1b43 | In a titration in Benin City, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.4 mol/dm³ NaOH neutralizes 40 cm³ of 0.2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.2 × 40 ÷ 0.4 = 20 cm³. Final answer: 20 cm³. | [
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muta2_0d46a2dc2e770f89afc5948a | In a titration in Monrovia, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1 mol/dm³ NaOH neutralizes 80 cm³ of 0.8 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.8 × 80 ÷ 1 = 64 cm³. Final answer: 64 cm³. | [
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muta2_efb77d6066fd3e35fc36759d | In a titration in Accra, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.8 mol/dm³ NaOH neutralizes 40 cm³ of 2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 2 × 40 ÷ 0.8 = 100 cm³. Final answer: 100 cm³. | [
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muta2_bfdaa56d3d4f1d08a82cc52b | In a titration in Tamale, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 221 cm³ of 1.9 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.9 × 221 ÷ 1.7 = 247 cm³. Final answer: 247 cm³. | [
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muta2_7329a47ffa1d9b8f9beaacf9 | In a titration in Abeokuta, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.2 mol/dm³ NaOH neutralizes 30 cm³ of 0.1 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.1 × 30 ÷ 0.2 = 15 cm³. Final answer: 15 cm³. | [
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muta2_2337c7b571a2c11c64c89c21 | In a titration in Bo, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.2 mol/dm³ NaOH neutralizes 26 cm³ of 1.8 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.8 × 26 ÷ 0.2 = 234 cm³. Final answer: 234 cm³. | [
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},
{
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muta2_28b9374a017da4b08f2d342e | In a titration in Abeokuta, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.4 mol/dm³ NaOH neutralizes 32 cm³ of 1.7 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.7 × 32 ÷ 0.4 = 136 cm³. Final answer: 136 cm³. | [
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},
{
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muta2_a4813d6a6545a85a3a08ef0e | In a titration in Benin City, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.8 mol/dm³ NaOH neutralizes 234 cm³ of 1.3 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.3 × 234 ÷ 1.8 = 169 cm³. Final answer: 169 cm³. | [
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},
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muta2_e68e1ce0e44df56b83b2f37a | In a titration in Benin City, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 2 mol/dm³ NaOH neutralizes 200 cm³ of 0.8 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.8 × 200 ÷ 2 = 80 cm³. Final answer: 80 cm³. | [
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muta2_1387e9eb0b2a87b489ba4bfb | In a titration in Ibadan, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.9 mol/dm³ NaOH neutralizes 228 cm³ of 0.1 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.1 × 228 ÷ 1.9 = 12 cm³. Final answer: 12 cm³. | [
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muta2_4bbf10626aa558eee5556f5c | In a titration in Abeokuta, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.8 mol/dm³ NaOH neutralizes 56 cm³ of 1.5 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.5 × 56 ÷ 0.8 = 105 cm³. Final answer: 105 cm³. | [
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muta2_af7eb656a44f34b7c4e23344 | In a titration in Tamale, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.1 mol/dm³ NaOH neutralizes 11 cm³ of 0.7 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.7 × 11 ÷ 0.1 = 77 cm³. Final answer: 77 cm³. | [
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muta2_8045509eeaf2d60ea0b38a58 | In a titration in Accra, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.8 mol/dm³ NaOH neutralizes 72 cm³ of 1.8 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.8 × 72 ÷ 0.8 = 162 cm³. Final answer: 162 cm³. | [
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muta2_8f2948b0a425696cc8db88d7 | In a titration in Onitsha, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1 mol/dm³ NaOH neutralizes 50 cm³ of 0.3 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.3 × 50 ÷ 1 = 15 cm³. Final answer: 15 cm³. | [
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{
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muta2_808a9018c376a27ed8045db0 | In a titration in Lagos, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.6 mol/dm³ NaOH neutralizes 90 cm³ of 0.9 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.9 × 90 ÷ 0.6 = 135 cm³. Final answer: 135 cm³. | [
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muta2_99dfbc874fe15f6e2e9481d5 | In a titration in Lagos, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.7 mol/dm³ NaOH neutralizes 91 cm³ of 0.9 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.9 × 91 ÷ 0.7 = 117 cm³. Final answer: 117 cm³. | [
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},
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muta2_7e138046658bd750f4e3b314 | In a titration in Tamale, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.8 mol/dm³ NaOH neutralizes 270 cm³ of 0.1 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.1 × 270 ÷ 1.8 = 15 cm³. Final answer: 15 cm³. | [
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},
{
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muta2_78fd2bee9e85c4bbf77ad0ca | In a titration in Lagos, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 102 cm³ of 1.9 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.9 × 102 ÷ 1.7 = 114 cm³. Final answer: 114 cm³. | [
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muta2_02bccf7d673b25bd4f9e7461 | In a titration in Ilorin, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.4 mol/dm³ NaOH neutralizes 52 cm³ of 0.7 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.7 × 52 ÷ 0.4 = 91 cm³. Final answer: 91 cm³. | [
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muta2_7d2fc9a341aaa127787829c5 | In a titration in Onitsha, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 2 mol/dm³ NaOH neutralizes 180 cm³ of 0.1 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.1 × 180 ÷ 2 = 9 cm³. Final answer: 9 cm³. | [
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muta2_5a76eb526c05948d53b955d6 | In a titration in Kumasi, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.9 mol/dm³ NaOH neutralizes 285 cm³ of 0.5 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.5 × 285 ÷ 1.9 = 75 cm³. Final answer: 75 cm³. | [
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},
{
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muta2_37a29a7faa6f7e3a13ca93eb | In a titration in Bo, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.5 mol/dm³ NaOH neutralizes 105 cm³ of 0.6 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.6 × 105 ÷ 1.5 = 42 cm³. Final answer: 42 cm³. | [
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{
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muta2_905d81a6588f9595578321d4 | In a titration in Benin City, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.6 mol/dm³ NaOH neutralizes 208 cm³ of 1.7 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.7 × 208 ÷ 1.6 = 221 cm³. Final answer: 221 cm³. | [
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},
{
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muta2_247925d9a99a2a6aef8210af | In a titration in Tamale, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.1 mol/dm³ NaOH neutralizes 66 cm³ of 0.1 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.1 × 66 ÷ 1.1 = 6 cm³. Final answer: 6 cm³. | [
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},
{
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muta2_c8d7ea2aa1268738dbccb334 | In a titration in Kano, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.2 mol/dm³ NaOH neutralizes 14 cm³ of 0.7 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.7 × 14 ÷ 0.2 = 49 cm³. Final answer: 49 cm³. | [
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},
{
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muta2_eb3bdc6d98cc468da56690b7 | In a titration in Freetown, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.3 mol/dm³ NaOH neutralizes 18 cm³ of 1.1 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.1 × 18 ÷ 0.3 = 66 cm³. Final answer: 66 cm³. | [
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},
{
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"content": "NaOH volume = 1.1 × 18 ÷ 0.3 = 66 cm³.... | 66 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
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muta2_7e21727f5f6a7628eef8ca61 | In a titration in Freetown, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.9 mol/dm³ NaOH neutralizes 228 cm³ of 1.3 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.3 × 228 ÷ 1.9 = 156 cm³. Final answer: 156 cm³. | [
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},
{
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muta2_aebe6d489a165d26a31b613b | In a titration in Lagos, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.1 mol/dm³ NaOH neutralizes 11 cm³ of 0.2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.2 × 11 ÷ 0.1 = 22 cm³. Final answer: 22 cm³. | [
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muta2_2199158af3879afd21eec4dc | In a titration in Lagos, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.1 mol/dm³ NaOH neutralizes 165 cm³ of 0.6 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.6 × 165 ÷ 1.1 = 90 cm³. Final answer: 90 cm³. | [
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muta2_6b283f6fe0b0ed0ed128f04f | In a titration in Monrovia, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 85 cm³ of 1.2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.2 × 85 ÷ 1.7 = 60 cm³. Final answer: 60 cm³. | [
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muta2_6cad459d20db30da7031641d | In a titration in Ibadan, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.7 mol/dm³ NaOH neutralizes 77 cm³ of 1.7 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.7 × 77 ÷ 0.7 = 187 cm³. Final answer: 187 cm³. | [
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muta2_d11ec49b2dc4a8a3803b08a1 | In a titration in Onitsha, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.5 mol/dm³ NaOH neutralizes 50 cm³ of 1.4 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.4 × 50 ÷ 0.5 = 140 cm³. Final answer: 140 cm³. | [
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muta2_69b2792177065eaee096e73e | In a titration in Kumasi, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.4 mol/dm³ NaOH neutralizes 40 cm³ of 0.2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.2 × 40 ÷ 0.4 = 20 cm³. Final answer: 20 cm³. | [
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},
{
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muta2_59291cf6edad52a469b74916 | In a titration in Accra, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.9 mol/dm³ NaOH neutralizes 133 cm³ of 0.2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.2 × 133 ÷ 1.9 = 14 cm³. Final answer: 14 cm³. | [
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},
{
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muta2_5b1b70eaf1d98d19b30efeca | In a titration in Abeokuta, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.9 mol/dm³ NaOH neutralizes 114 cm³ of 0.7 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.7 × 114 ÷ 1.9 = 42 cm³. Final answer: 42 cm³. | [
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},
{
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muta2_4dfa385b748011c28cfad0ec | In a titration in Ilorin, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.1 mol/dm³ NaOH neutralizes 165 cm³ of 1.9 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.9 × 165 ÷ 1.1 = 285 cm³. Final answer: 285 cm³. | [
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},
{
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muta2_adb92917d40b56225266bad3 | In a titration in Tamale, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.3 mol/dm³ NaOH neutralizes 130 cm³ of 1.7 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.7 × 130 ÷ 1.3 = 170 cm³. Final answer: 170 cm³. | [
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muta2_60d9e6c7fb00d500b6eff36c | In a titration in Kumasi, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 2 mol/dm³ NaOH neutralizes 220 cm³ of 0.2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.2 × 220 ÷ 2 = 22 cm³. Final answer: 22 cm³. | [
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muta2_ba9c85729eb34b2e75297d81 | In a titration in Freetown, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.2 mol/dm³ NaOH neutralizes 18 cm³ of 0.3 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.3 × 18 ÷ 0.2 = 27 cm³. Final answer: 27 cm³. | [
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muta2_caf73fd546c3ea7773ba4b36 | In a titration in Kumasi, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.2 mol/dm³ NaOH neutralizes 18 cm³ of 1.4 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.4 × 18 ÷ 0.2 = 126 cm³. Final answer: 126 cm³. | [
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muta2_ff60a8cac083dd0de37254ad | In a titration in Benin City, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.6 mol/dm³ NaOH neutralizes 96 cm³ of 0.1 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.1 × 96 ÷ 1.6 = 6 cm³. Final answer: 6 cm³. | [
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muta2_38aad64732189c4056f11075 | In a titration in Lagos, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.1 mol/dm³ NaOH neutralizes 110 cm³ of 0.2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.2 × 110 ÷ 1.1 = 20 cm³. Final answer: 20 cm³. | [
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muta2_a20001d91aec7152baf5df40 | In a titration in Accra, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.2 mol/dm³ NaOH neutralizes 18 cm³ of 0.1 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.1 × 18 ÷ 0.2 = 9 cm³. Final answer: 9 cm³. | [
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muta2_6f52234614e13ab6253531d9 | In a titration in Onitsha, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.6 mol/dm³ NaOH neutralizes 208 cm³ of 0.2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.2 × 208 ÷ 1.6 = 26 cm³. Final answer: 26 cm³. | [
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muta2_612e20b97857e3aeaffd6679 | In a titration in Lagos, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.7 mol/dm³ NaOH neutralizes 42 cm³ of 0.3 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.3 × 42 ÷ 0.7 = 18 cm³. Final answer: 18 cm³. | [
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muta2_90fc30fedafa2117bc63700d | In a titration in Kumasi, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.5 mol/dm³ NaOH neutralizes 75 cm³ of 0.7 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.7 × 75 ÷ 0.5 = 105 cm³. Final answer: 105 cm³. | [
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muta2_fd681fbe8896f5dfde8bbafd | In a titration in Lagos, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.7 mol/dm³ NaOH neutralizes 77 cm³ of 1.8 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.8 × 77 ÷ 0.7 = 198 cm³. Final answer: 198 cm³. | [
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muta2_c7f3a876b1e294d8b6d1759f | In a titration in Accra, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.7 mol/dm³ NaOH neutralizes 49 cm³ of 0.2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.2 × 49 ÷ 0.7 = 14 cm³. Final answer: 14 cm³. | [
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muta2_ca12d84684e499f394741887 | In a titration in Abeokuta, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 2 mol/dm³ NaOH neutralizes 220 cm³ of 1.9 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.9 × 220 ÷ 2 = 209 cm³. Final answer: 209 cm³. | [
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muta2_1d6d3a03a97716d20c4104e3 | In a titration in Bo, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.4 mol/dm³ NaOH neutralizes 36 cm³ of 0.5 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.5 × 36 ÷ 0.4 = 45 cm³. Final answer: 45 cm³. | [
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muta2_d5cd0e44ccfe84f92eb88d8b | In a titration in Abeokuta, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.3 mol/dm³ NaOH neutralizes 21 cm³ of 0.7 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.7 × 21 ÷ 0.3 = 49 cm³. Final answer: 49 cm³. | [
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muta2_82b62fc7161758516007728f | In a titration in Accra, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.9 mol/dm³ NaOH neutralizes 114 cm³ of 0.9 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.9 × 114 ÷ 1.9 = 54 cm³. Final answer: 54 cm³. | [
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muta2_512fb66de734f97d624013a3 | In a titration in Benin City, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.6 mol/dm³ NaOH neutralizes 54 cm³ of 1.7 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.7 × 54 ÷ 0.6 = 153 cm³. Final answer: 153 cm³. | [
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muta2_e4aa8f8d4c116fb958ccd5ae | In a titration in Kumasi, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.5 mol/dm³ NaOH neutralizes 225 cm³ of 0.1 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.1 × 225 ÷ 1.5 = 15 cm³. Final answer: 15 cm³. | [
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muta2_6b7bd9721405e5865d17a9db | In a titration in Kano, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.6 mol/dm³ NaOH neutralizes 48 cm³ of 1.2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.2 × 48 ÷ 0.6 = 96 cm³. Final answer: 96 cm³. | [
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muta2_955fa73a3f1de1ac1f881d0d | In a titration in Freetown, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.3 mol/dm³ NaOH neutralizes 36 cm³ of 1.4 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.4 × 36 ÷ 0.3 = 168 cm³. Final answer: 168 cm³. | [
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muta2_a3cd23b16b52e409a29d1e7d | In a titration in Freetown, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.3 mol/dm³ NaOH neutralizes 117 cm³ of 1.5 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.5 × 117 ÷ 1.3 = 135 cm³. Final answer: 135 cm³. | [
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muta2_94cb4d82fdde4d5e6c10d499 | In a titration in Kano, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.4 mol/dm³ NaOH neutralizes 154 cm³ of 0.6 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.6 × 154 ÷ 1.4 = 66 cm³. Final answer: 66 cm³. | [
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muta2_7a92ac9be979461e5e8e4798 | In a titration in Ilorin, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.9 mol/dm³ NaOH neutralizes 135 cm³ of 1.6 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.6 × 135 ÷ 0.9 = 240 cm³. Final answer: 240 cm³. | [
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muta2_cec37183f589a9751ae69509 | In a titration in Bo, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 85 cm³ of 1.4 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.4 × 85 ÷ 1.7 = 70 cm³. Final answer: 70 cm³. | [
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muta2_fb60ab175770336684d3d3c6 | In a titration in Accra, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.9 mol/dm³ NaOH neutralizes 45 cm³ of 0.8 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.8 × 45 ÷ 0.9 = 40 cm³. Final answer: 40 cm³. | [
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muta2_53813d4b65f16836c1877295 | In a titration in Kumasi, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.8 mol/dm³ NaOH neutralizes 198 cm³ of 0.2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.2 × 198 ÷ 1.8 = 22 cm³. Final answer: 22 cm³. | [
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muta2_9f5ee267e6f79973b4bb6cdf | In a titration in Benin City, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.2 mol/dm³ NaOH neutralizes 10 cm³ of 1.1 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.1 × 10 ÷ 0.2 = 55 cm³. Final answer: 55 cm³. | [
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},
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muta2_3219b03131454408fdfea53e | In a titration in Accra, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.8 mol/dm³ NaOH neutralizes 88 cm³ of 0.1 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.1 × 88 ÷ 0.8 = 11 cm³. Final answer: 11 cm³. | [
{
"role": "user",
"content": "In a titration in Accra, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.8 mol/dm³ NaOH neutralizes 88 cm³ of 0.1 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 0.1 × 88 ÷ 0.8 = 11 cm³. Fi... | 11 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
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muta2_69936e2bff24d56f04acad47 | In a titration in Kano, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.6 mol/dm³ NaOH neutralizes 160 cm³ of 0.6 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.6 × 160 ÷ 1.6 = 60 cm³. Final answer: 60 cm³. | [
{
"role": "user",
"content": "In a titration in Kano, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.6 mol/dm³ NaOH neutralizes 160 cm³ of 0.6 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 0.6 × 160 ÷ 1.6 = 60 cm³. F... | 60 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
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"authority": "Muta normalized public-topic taxonomy",
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muta2_9c936a5fc06e6190d8c18718 | In a titration in Kano, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.3 mol/dm³ NaOH neutralizes 78 cm³ of 0.9 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.9 × 78 ÷ 1.3 = 54 cm³. Final answer: 54 cm³. | [
{
"role": "user",
"content": "In a titration in Kano, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.3 mol/dm³ NaOH neutralizes 78 cm³ of 0.9 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 0.9 × 78 ÷ 1.3 = 54 cm³. Fin... | 54 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
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muta2_0c1bf3541ab7481f4d23ed6f | In a titration in Onitsha, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 255 cm³ of 0.8 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.8 × 255 ÷ 1.7 = 120 cm³. Final answer: 120 cm³. | [
{
"role": "user",
"content": "In a titration in Onitsha, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 255 cm³ of 0.8 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 0.8 × 255 ÷ 1.7 = 120 cm... | 120 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
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muta2_e94c6a98155e8b291df8239c | In a titration in Accra, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 102 cm³ of 1.9 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.9 × 102 ÷ 1.7 = 114 cm³. Final answer: 114 cm³. | [
{
"role": "user",
"content": "In a titration in Accra, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 102 cm³ of 1.9 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 1.9 × 102 ÷ 1.7 = 114 cm³.... | 114 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
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} | {
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"semantic_cluster_id": "formula:neutralization_volume",
"license": "MIT",
"synthetic": true,
"transform":... | {
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"method": "neutralization_volume",
"expected": "114 cm³",
"observed": "114 cm³",
"verifier_version": "muta-stem-v2.4",
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"base_concentration_tenths": 17,
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},
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muta2_2b4cf7c9f9b91fc8a7cf2c98 | In a titration in Lagos, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.1 mol/dm³ NaOH neutralizes 8 cm³ of 1.8 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.8 × 8 ÷ 0.1 = 144 cm³. Final answer: 144 cm³. | [
{
"role": "user",
"content": "In a titration in Lagos, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.1 mol/dm³ NaOH neutralizes 8 cm³ of 1.8 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 1.8 × 8 ÷ 0.1 = 144 cm³. Fin... | 144 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
"exam_era": "contemporary",
"alignment": "original item; topic-level alignment only"
} | {
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"transform":... | {
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"method": "neutralization_volume",
"expected": "144 cm³",
"observed": "144 cm³",
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muta2_93e24c67bbc8bd38b77cd83e | In a titration in Onitsha, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.1 mol/dm³ NaOH neutralizes 143 cm³ of 2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 2 × 143 ÷ 1.1 = 260 cm³. Final answer: 260 cm³. | [
{
"role": "user",
"content": "In a titration in Onitsha, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.1 mol/dm³ NaOH neutralizes 143 cm³ of 2 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 2 × 143 ÷ 1.1 = 260 cm³. F... | 260 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
"exam_era": "contemporary",
"alignment": "original item; topic-level alignment only"
} | {
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"transform":... | {
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"method": "neutralization_volume",
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"observed": "260 cm³",
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muta2_88c33cd6d45b9cb1dbfe0c03 | In a titration in Abeokuta, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.3 mol/dm³ NaOH neutralizes 117 cm³ of 1.5 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.5 × 117 ÷ 1.3 = 135 cm³. Final answer: 135 cm³. | [
{
"role": "user",
"content": "In a titration in Abeokuta, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.3 mol/dm³ NaOH neutralizes 117 cm³ of 1.5 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 1.5 × 117 ÷ 1.3 = 135 c... | 135 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
"exam_era": "contemporary",
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"license": "MIT",
"synthetic": true,
"transform":... | {
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"method": "neutralization_volume",
"expected": "135 cm³",
"observed": "135 cm³",
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"acid_volume": 117,
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End of preview.
Muta STEM SFT Full
This dataset covers mathematics, physics, chemistry, biology, and integrated science in five tutoring styles used in training the Muta Tutor model.
Snapshot
| Property | Value |
|---|---|
| Rows | 2,500,350 |
| JSONL shards | 102 |
| Decompressed data | 6,236,652,830 bytes (~5.81 GiB) |
| Hub data file | 315,401,825 bytes (~300.8 MiB), Zstandard |
| Language | English |
| Candidate train split | 2,453,738 |
| Template holdout split | 46,612 |
| Fingerprint | 3a14a35a471b8763fd81d3e0124d861df64387a73293d8efa43526a075e5bc3d |
| Source | Rows |
|---|---|
| Muta verified STEM v2 | 1,085,000 |
| DeepMind Mathematics | 1,052,000 |
| TemplateGSM | 350,000 |
| GSM8K | 6,500 |
| QASC | 6,500 |
| WAEC questions | 350 |
| Subject | Rows | Tutoring style | Rows |
|---|---|---|---|
| Mathematics | 1,680,061 | Concise answer | 1,167,001 |
| Physics | 292,980 | Worked solution | 790,846 |
| Chemistry | 227,856 | Exam marking scheme | 217,002 |
| Biology | 227,853 | Misconception correction | 217,000 |
| Integrated science | 71,600 | Socratic hint | 108,501 |
Important: not a training split
Do not train on this repository as a whole: whole_artifact_training_authorized is false. It
intentionally retains audit-required candidates, template holdouts, and rows that are not
training-eligible. Apply each row's split, verification.training_eligible and the
exact-row rules in manifest.json, or use the separate quality-first SFT repository.
Record format
Every row has prompt, completion, messages, answer, subject, topic, difficulty,
pedagogy, curriculum, provenance, verification, contamination, and tokenization
metadata.
from datasets import load_dataset
warehouse = load_dataset(
"timiiowolabi/muta_tutor_full_dataset",
"warehouse",
split="warehouse",
)
The provenance-code/, provenance-holdouts/, and provenance-source-evidence/ directories bind
the recipes, schemas, source receipts, holdout evidence, and reproduction code used to build this dataset.
The Hub data file is the lossless concatenation of the 102 manifest shards in listed
order; HUGGINGFACE_COMPRESSION.json records its hash and byte counts.
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